2009-09-30 22:09
打印出象Linux的tree命令一样的目录树结构程序
差点找不找了,贴出来。不过已经集成到Ulipad中了。

在目录浏览窗口中的Print Directory Tree就是。执行后会将当前选中的目录结构输出到messages窗口。
代码如下:
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#! /usr/bin/env python
#coding=utf-8
import os, sys
import fnmatch
space = 4
stack = {0:''}
def path_line(level, path, is_dir, is_last):
s = []
leading = stack[level-1]
if is_dir:
path = path+'/'
if is_last:
s.append(leading + '`-- ' + path)
leading += ' '
else:
s.append(leading + '|-- ' + path)
leading += '| '
stack[level] = leading
return ''.join(s)
def walk(dir, level=1, skips=['.svn', '*.pyc']):
r = []
dirs = [x for x in os.listdir(dir) if not any([fnmatch.fnmatch(x, y) for y in skips])]
num = len(dirs)
for i, path in enumerate(sorted(dirs, cmp=lambda x,y: cmp(x.lower(), y.lower()))):
p = os.path.join(dir, path)
flag = os.path.isdir(p)
r.append(path_line(level, path, flag, i==num-1))
if flag:
r.extend(walk(p, level+1, skips=skips))
return r
if __name__ == '__main__':
if len(sys.argv) == 1:
path = '.'
else:
path = sys.argv[1]
print path
print '\n'.join(walk(path))

在目录浏览窗口中的Print Directory Tree就是。执行后会将当前选中的目录结构输出到messages窗口。
代码如下:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
#! /usr/bin/env python
#coding=utf-8
import os, sys
import fnmatch
space = 4
stack = {0:''}
def path_line(level, path, is_dir, is_last):
s = []
leading = stack[level-1]
if is_dir:
path = path+'/'
if is_last:
s.append(leading + '`-- ' + path)
leading += ' '
else:
s.append(leading + '|-- ' + path)
leading += '| '
stack[level] = leading
return ''.join(s)
def walk(dir, level=1, skips=['.svn', '*.pyc']):
r = []
dirs = [x for x in os.listdir(dir) if not any([fnmatch.fnmatch(x, y) for y in skips])]
num = len(dirs)
for i, path in enumerate(sorted(dirs, cmp=lambda x,y: cmp(x.lower(), y.lower()))):
p = os.path.join(dir, path)
flag = os.path.isdir(p)
r.append(path_line(level, path, flag, i==num-1))
if flag:
r.extend(walk(p, level+1, skips=skips))
return r
if __name__ == '__main__':
if len(sys.argv) == 1:
path = '.'
else:
path = sys.argv[1]
print path
print '\n'.join(walk(path))