百度首页 | 百度空间
 
查看文章
 
逆向技术入门一例
2008-07-09 16:51

最近对逆向分析技术有了了解。。非常感兴趣。

分析一个例子吧。。

什么功能都没有。。练手的东西。。呵

提示错误信息是:Incorrect try again!

载入OD直接查找这个字符串。。。下断点

0040155C |. 8D45 F4       LEA EAX,DWORD PTR SS:[EBP-C]                                      ; strlen这个函数的参数
0040155F |. 50            PUSH EAX                                                          ; /压栈
00401560 |. FF15 04204000 CALL DWORD PTR DS:[<&KERNEL32.lstrlenA>]                          ; \lstrlenA
00401566 |. 8945 F0       MOV DWORD PTR SS:[EBP-10],EAX
00401569 |. 837D F0 01    CMP DWORD PTR SS:[EBP-10],1                                       ; 返回跟1比较
0040156D |. 73 16         JNB SHORT CRACKME.00401585                                        ; 不小于1向下跳
0040156F |. 6A 40         PUSH 40
00401571 |. 68 2C304000   PUSH CRACKME.0040302C                                             ; crackme
00401576 |. 68 34304000   PUSH CRACKME.00403034                                             ; enter registration number
0040157B |. 8B4D E0       MOV ECX,DWORD PTR SS:[EBP-20]
0040157E |. E8 7B050000   CALL <JMP.&MFC42.#4224_?MessageBoxA@CWnd@@QAEHPBD0I@Z>
00401583 |. EB 3C         JMP SHORT CRACKME.004015C1
00401585 |> 8D4D E4       LEA ECX,DWORD PTR SS:[EBP-1C]                                     ; strcmp的第一个参数
00401588 |. 51            PUSH ECX                                                          ; /String2
00401589 |. 8D55 F4       LEA EDX,DWORD PTR SS:[EBP-C]                                      ; |第二个参数
0040158C |. 52            PUSH EDX                                                          ; |String1
0040158D |. FF15 00204000 CALL DWORD PTR DS:[<&KERNEL32.lstrcmpA>]                          ; \lstrcmpA
00401593 |. 85C0          TEST EAX,EAX
00401595      75 16         JNZ SHORT CRACKME.004015AD                                        ; 关键跳
00401597 |. 6A 40         PUSH 40
00401599 |. 68 50304000   PUSH CRACKME.00403050                                             ; crackme
0040159E |. 68 58304000   PUSH CRACKME.00403058                                             ; correct way to go!!
004015A3 |. 8B4D E0       MOV ECX,DWORD PTR SS:[EBP-20]
004015A6 |. E8 53050000   CALL <JMP.&MFC42.#4224_?MessageBoxA@CWnd@@QAEHPBD0I@Z>
004015AB |. EB 14         JMP SHORT CRACKME.004015C1
004015AD |> 6A 40         PUSH 40
004015AF |. 68 6C304000   PUSH CRACKME.0040306C                                             ; crackme
004015B4 |. 68 74304000   PUSH CRACKME.00403074                                             ; incorrect try again!!
004015B9 |. 8B4D E0       MOV ECX,DWORD PTR SS:[EBP-20]
004015BC |. E8 3D050000   CALL <JMP.&MFC42.#4224_?MessageBoxA@CWnd@@QAEHPBD0I@Z>
004015C1 |> 8BE5          MOV ESP,EBP
004015C3 |. 5D            POP EBP
004015C4 \. C3            RETN


类别:加密与解密 | 添加到搜藏 | 浏览() | 评论 (2)
 
最近读者:
 
网友评论:
1
2008-07-11 08:57
无非就是用PE explorer 然后懂一点win32汇编,开始关注你的博客,博主加油
 
2
2008-07-11 10:48
只是入门级别的。。练练手
 
发表评论:
姓 名:
网址或邮箱: (选填)
内 容:
验证码:
 

     

©2008 Baidu